Number of occurrence Java
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PROGRAM TO COUNT THE NUMBER OF OCCURRENCES (OR FREQUENCY) IN A SORTED ARRAY
class MAIN { /* if x is present in arr[] then returns the count of occurrences of x, otherwise returns -1. */ static int count(int arr[], int x, int n) { // index of first occurrence of x in arr[0..n-1] int i; // index of last occurrence of x in arr[0..n-1] int j; /* get the index of first occurrence of x */ i = first(arr, 0, n-1, x, n); /* If x doesn't exist in arr[] then return -1 */ if(i == -1) return i; /* Else get the index of last occurrence of x. Note that we are only looking in the subarray after first occurrence */ j = last(arr, i, n-1, x, n); /* return count */ return j-i+1; } /* if x is present in arr[] then returns the index of FIRST occurrence of x in arr[0..n-1], otherwise returns -1 */ static int first(int arr[], int low, int high, int x, int n) { if(high >= low) { /*low + (high - low)/2;*/ int mid = (low + high)/2; if( ( mid == 0 || x > arr[mid-1]) && arr[mid] == x) return mid; else if(x > arr[mid]) return first(arr, (mid + 1), high, x, n); else return first(arr, low, (mid -1), x, n); } return -1; } /* if x is present in arr[] then returns the index of LAST occurrence of x in arr[0..n-1], otherwise returns -1 */ static int last(int arr[], int low, int high, int x, int n) { if(high >= low) { /*low + (high - low)/2;*/ int mid = (low + high)/2; if( ( mid == n-1 || x < arr[mid+1]) && arr[mid] == x ) return mid; else if(x < arr[mid]) return last(arr, low, (mid -1), x, n); else return last(arr, (mid + 1), high, x, n); } return -1; } public static void main(String args[]) { int arr[] = {1, 2, 2, 3, 3, 3, 3}; // Element to be counted in arr[] int x = 3; int n = arr.length; int c = count(arr, x, n); System.out.println(x+" occurs "+c+" times"); } }
OUTPUT
3 occurs 4 times
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