Triplet Sum in Array Python
PROGRAM TO FIND A TRIPLET THAT SUM TO A GIVEN VALUE
OUTPUT
Triplet is 4, 8, 10
# returns true if there is triplet with sum equal # to 'sum' present in A[]. Also, prints the triplet def find3Numbers(A, arr_size, sum): for i in range(0, arr_size-1): # Find pair in subarray A[i + 1..n-1] # with sum equal to sum - A[i] s = set() curr_sum = sum - A[i] for j in range(i + 1, arr_size): if (curr_sum - A[j]) in s: print("Triplet is", A[i], ", ", A[j], ", ", curr_sum-A[j]) return True s.add(A[j]) return False # Driver program to test above function A = [1, 4, 45, 6, 10, 8] sum = 22arr_size = len(A) find3Numbers(A, arr_size, sum)
Triplet is 4, 8, 10
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