Count the triplets Java

PROGRAM TO COUNT TRIPLETS SUCH THAT ONE OF THE NUMBERS CAN BE WRITTEN AS SUM OF OTHER TWO



class Main {
  
    // Function to count the number of ways
    // to choose the triples
    static int countWays(int[] arr, int n)
    {
        // compute the max value in the array
        // and create frequency array of size
        // max_val + 1.
        // We can also use HashMap to store
        // frequencies. We have used an array
        // to keep remaining code simple.
        int max_val = 0;
        for (int i = 0; i < n; i++)
            max_val = Math.max(max_val, arr[i]);
        int[] freq = new int[max_val + 1];
        for (int i = 0; i < n; i++)
            freq[arr[i]]++;
  
        int ans = 0; // stores the number of ways
  
        // Case 1: 0, 0, 0
        ans += freq[0] * (freq[0] - 1) * (freq[0] - 2) / 6;
  
        // Case 2: 0, x, x
        for (int i = 1; i <= max_val; i++)
            ans += freq[0] * freq[i] * (freq[i] - 1) / 2;
  
        // Case 3: x, x, 2*x
        for (int i = 1; 2 * i <= max_val; i++)
            ans += freq[i] * (freq[i] - 1) / 2 * freq[2 * i];
  
        // Case 4: x, y, x + y
        // iterate through all pairs (x, y)
        for (int i = 1; i <= max_val; i++) {
            for (int j = i + 1; i + j <= max_val; j++)
                ans += freq[i] * freq[j] * freq[i + j];
        }
  
        return ans;
    }
  
    // Driver code
    public static void main(String[] args)
    {
        int[] arr = new int[] { 1, 2, 3, 4, 5 };
        int n = arr.length;
        System.out.println(countWays(arr, n));
    }
}


OUTPUT
4

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