Spirally traversing a matrix Python

PROGRAM TO PRINT MATRIX IN SPIRAL FORM

def printdata(arr, i, j, m, n):

  

    # If i or j lies outside the matrix

    if (i >= m or j >= n):

        return

  

    # Print First Row

    for p in range(i, n):

        print(arr[i][p], end=" ")

  

    # Print Last Column

    for p in range(i + 1, m):

        print(arr[p][n - 1], end=" ")

  

    # Print Last Row, if Last and

    # First Row are not same

    if ((m - 1) != i):

        for p in range(n - 2, j - 1, -1):

            print(arr[m - 1][p], end=" ")

  

    # Print First Column, if Last and

    # First Column are not same

    if ((n - 1) != j):

        for p in range(m - 2, i, -1):

            print(arr[p][j], end=" ")

  

    printdata(arr, i + 1, j + 1, m - 1, n - 1)

  

  

# Driver code

R = 4

C = 4

arr = [[1, 2, 3, 4],

       [5, 6, 7, 8],

       [9, 10, 11, 12],

       [13, 14, 15, 16]]

  

# Function Call

printdata(arr, 0, 0, R, C)







OUTPUT

1 2 3 4 8 12 16 15 14 13 9 5 6 7 11 10 

CREDITS: https://www.geeksforgeeks.org/print-a-given-matrix-in-spiral-form/