Pairwise swap elements of a linked list Python

PROGRAM TO SWAP ELEMENTS PAIRWISE OF A GIVEN LINKED LIST



# Node class 
class Node:
  
    # Constructor to initialize the node object
    def __init__(self, data):
        self.data = data
        self.next = None
  
class LinkedList:
  
    # Function to initialize head
    def __init__(self):
        self.head = None
  
    # Function to pairwise swap elements of a linked list
    def pairwiseSwap(self):
        temp = self.head
         
        # There are no nodes in linked list
        if temp is None:
            return 
          
        # Traverse furthur only if there are at least two
        # left
        while(temp is not None and temp.next is not None):
              
            # If both nodes are same,
            # no need to swap data
            if(temp.data == temp.next.data):
                  
                # Move temp by 2 to the next pair
                temp = temp.next.next
            else:
                  
                # Swap data of node with its next node's data
                temp.data, temp.next.data = temp.next.data, temp.data
                  
                # Move temp by 2 to the next pair
                temp = temp.next.next
         
    # Function to insert a new node at the beginning
    def push(self, new_data):
        new_node = Node(new_data)
        new_node.next = self.head
        self.head = new_node
  
    # Utility function to prit the linked LinkedList
    def printList(self):
        temp = self.head
        while(temp):
            print temp.data,
            temp = temp.next
  
  
# Driver program
llist = LinkedList()
llist.push(5)
llist.push(4)
llist.push(3)
llist.push(2)
llist.push(1)
  
print "Linked list before calling pairWiseSwap() "
llist.printList()
  
llist.pairwiseSwap()
  
print  "\nLinked list after calling pairWiseSwap()"
llist.printList()


OUTPUT
Linked List before calling pairWiseSwap() 
1 2 3 4 5 
Linked List after calling pairWiseSwap() 
2 1 4 3 5 

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