Detect Cycle in a Directed Graph Python

PROGRAM TO DETECT CYCLE IN A DIRECTED GRAPH



from collections import defaultdict
 
class Graph():
    def __init__(self,vertices):
        self.graph = defaultdict(list)
        self.V = vertices
 
    def addEdge(self,u,v):
        self.graph[u].append(v)
 
    def isCyclicUtil(self, v, visited, recStack):
 
        # Mark current node as visited and
        # adds to recursion stack
        visited[v] = True
        recStack[v] = True
 
        # Recur for all neighbours
        # if any neighbour is visited and in
        # recStack then graph is cyclic
        for neighbour in self.graph[v]:
            if visited[neighbour] == False:
                if self.isCyclicUtil(neighbour, visited, recStack) == True:
                    return True
            elif recStack[neighbour] == True:
                return True
 
        # The node needs to be poped from
        # recursion stack before function ends
        recStack[v] = False
        return False
 
    # Returns true if graph is cyclic else false
    def isCyclic(self):
        visited = [False] * (self.V + 1)
        recStack = [False] * (self.V + 1)
        for node in range(self.V):
            if visited[node] == False:
                if self.isCyclicUtil(node,visited,recStack) == True:
                    return True
        return False
 
g = Graph(4)
g.addEdge(0, 1)
g.addEdge(0, 2)
g.addEdge(1, 2)
g.addEdge(2, 0)
g.addEdge(2, 3)
g.addEdge(3, 3)
if g.isCyclic() == 1:
    print "Graph has a cycle"
else:
    print "Graph has no cycle"


OUTPUT:
Graph contains cycle

Comments

Popular posts from this blog

Solve the Sudoku Python

Solve the Sudoku Java

Find Duplicates Java