Rod Cutting Python
PROGRAM TO DETERMINE MAXIMUM VALUE OBTAINABLE BY CUTTING UP THE ROD AND SELLING THE PIECES
OUTPUT:
Maximum Obtainable Value is 22n
INT_MIN = -32767# Returns the best obtainable price for a rod of length n and# price[] as prices of different piecesdef cutRod(price, n): val = [0 for x in range(n+1)] val[0] = 0 # Build the table val[] in bottom up manner and return # the last entry from the table for i in range(1, n+1): max_val = INT_MIN for j in range(i): max_val = max(max_val, price[j] + val[i-j-1]) val[i] = max_val return val[n]# Driver program to test above functionsarr = [1, 5, 8, 9, 10, 17, 17, 20]size = len(arr)print("Maximum Obtainable Value is " + str(cutRod(arr, size)))
Maximum Obtainable Value is 22n
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